If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(X^2+3X+1)(X^2-3X-3)=5
We move all terms to the left:
(X^2+3X+1)(X^2-3X-3)-(5)=0
We move all terms containing X to the left, all other terms to the right
(X^2+3X+1)(X^2-3X-3)=5
| y=5(10)+60 | | 3y-4=y-10 | | -7+n/5=1 | | -6(2+3x)=-30 | | 60=5(10)+b | | -9x-12=69 | | 19a=-38 | | 3y-5=2y-11 | | -1.2=2x-(-0.6) | | 7f+4=4f+1 | | 5(3y+2)=6-2(y-2) | | -8x+7=12x+27 | | 8r+7=3r-3 | | -8x+7=-12x-27 | | 8x+7=-12x-27 | | 3t+5=t+6 | | 2s-3=19 | | 7+5x+47=360 | | 9a+2=42 | | 24=-8+8x | | 1x^2-6x+12=0 | | 3p-5=p-3 | | 1x+(12*3)=3 | | -8x+7=12x-27 | | 11p+5=38 | | 8x+7=12x-27 | | 14+5w=39 | | 6p=-9+9 | | 7a+1=43 | | 8x+7=12x+27 | | F(n)=5n/3 | | 22z=7 |